keithcuda
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Homework Statement
- A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does the ball make it over the fence?
The discussion revolves around a physics problem involving projectile motion. A ball is thrown at an initial speed of 22 m/s at a 45-degree angle, with the question of whether it clears a 5-foot tall fence located 100 meters away.
The discussion is ongoing, with participants providing feedback on each other's reasoning and calculations. Some guidance has been offered regarding the interpretation of the equations and the need for clarity in explanations. Multiple interpretations of the problem are being explored, particularly concerning the ball's trajectory and the conditions for clearing the fence.
Participants express uncertainty about the calculations and the physical setup, including the significance of the angle of launch and the distance to the fence. There is mention of external resources that may have influenced their understanding of the problem.
keithcuda said:Homework Statement
- A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does the ball make it over the fence?
Homework Equations
View attachment 77761
The Attempt at a Solution
SteamKing said:You've written some numbers down, but whether they mean anything is another story.
What's the deal with vf - vi = -31.12? [You need to show units in your calculations always.] What does this even mean, in terms of the travel of the ball?
Roy Hobbs ;)Bystander said:Who's throwing? Randy Johnson? Or Warwick Davis?
Your attachment can't be opened.keithcuda said:Here is my image and drawing with all of the units shown.. Sorry for not including them earlier.
https://www.physicsforums.com/attachments/77770
keithcuda said:Here is my image and drawing with all of the units shown.. Sorry for not including them earlier.
https://www.physicsforums.com/attachments/77770View attachment 77771
Quantum Defect said:Ok, I understand what you are doing now.
On the line with Delta v, you are stating that at the point that the ball impacts the ground, the downward velocity is the same magnitude as the upward velocity at the launch, but with opposite direction. You use the calculated Delta v and g to calculate the time aloft, and you use the horizontal component of the velocity times the time aloft to calculate the distance traveled. You note that since the distance traveled (49 m) < 100 m, the ball hits the dirt in front of the wall.
This looks good to me.
I would suggest adding some words to describe the equations -- to show that you know what you are doing. If you screw up the calculation (arithmetic error) but have the correct physics, your professor might give you some partial credit...
OH boy! Ummm...TSny said:How high can that ball bounce?![]()

CWatters said:Playing the devil... Suppose the distance traveled had worked out at 102m. Would the ball have cleared the wall?
