Solving Bill's Elevator Mystery: Weight and Distance

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SUMMARY

The discussion centers on solving a physics problem involving Bill's apparent weight in an elevator over a 12-second interval. The key equations referenced include F = ma, which is essential for understanding the relationship between force, mass, and acceleration. Bill's original weight is determined by identifying the normal weight condition on the graph, which corresponds to constant speed. The confusion arises from differentiating between weight during acceleration and weight at rest, which is crucial for calculating distance traveled.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of apparent weight and its relation to acceleration
  • Familiarity with graph interpretation in physics
  • Basic concepts of kinematics and motion
NEXT STEPS
  • Review the concept of apparent weight in accelerating systems
  • Study kinematic equations for distance calculation under varying acceleration
  • Learn about graph analysis for motion and forces
  • Explore examples of elevators and their physics in real-world scenarios
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of motion in elevators.

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Homework Statement



Bill gets into an elevator on the 40th floor of a building and it begins moving at t = 0s. The figure shows his apparent weight over the next 12s.

Is the Elevator moving up or down originally?
What is his weight?
How far does he travel over the first 12 seconds

graph.jpg


Homework Equations


F = ma


The Attempt at a Solution



Part A is taken care of.

But for Part B (and therefore part C), I assumed that his weight at t = 0 was his mass, so divided that by gravity, but that answer was spit out (automated grading system). I'm assuming that this is because the elevator starts moving at 0, but if that's the case I'm not sure what to do about his original mass.

I know once I have that I can use the difference at each interval to find the acceleration and therefore distance, but it's the original mass that's confusing me.
 
Physics news on Phys.org
Three conditions are possible: upward acceleration (highest weight), constant speed (normal weight), and downward acceleration (lower weight). You should be able to pick out the middle one on the graph and that will be your normal weight.
 

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