Solving Billy and Speakers: 16m, 0.8m, 3000 Hz

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SUMMARY

The discussion focuses on solving a physics problem involving sound interference from two speakers positioned 16 meters from a wall and 0.8 meters apart, emitting a 3000 Hz sound. The wavelength is calculated to be 0.1143 meters using the formula λ = v/f, where v is the speed of sound (343 m/s). To find the distance Bill must walk to reach the m=1 maximum, the key is to determine the point where the distance from each speaker differs by half a wavelength (0.05715 meters). This involves applying geometric principles to locate the interference maxima along the wall.

PREREQUISITES
  • Understanding of wave properties, specifically wavelength and frequency.
  • Familiarity with sound interference concepts, including constructive and destructive interference.
  • Basic geometry skills to analyze distances and angles.
  • Knowledge of the speed of sound in air and its implications in wave calculations.
NEXT STEPS
  • Study the principles of sound wave interference and how to calculate interference patterns.
  • Learn about the relationship between frequency, wavelength, and the speed of sound in various mediums.
  • Explore geometric methods for solving problems involving distances and angles in wave interference scenarios.
  • Investigate practical applications of sound interference in acoustics and audio engineering.
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, sound engineers, and anyone interested in the practical applications of sound interference in real-world scenarios.

axgalloway
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Homework Statement



Two lound speakers are each located 16m from a wall and are 0.8m apart. They play a 3000 Hz sound, both speakers are in phase. Bill is located at the wall at the m=0 maximum of sound interference. If he walks along the wall, how far does he have to walk to hear m=1 maximum? (The speed of sound is 343 m/s.)


Homework Equations



2pi * (x2-x1) / lambda = 2mpi
vsound = lambda*f


The Attempt at a Solution



343 m/s = lambda*3000Hz
lambda= .1143 meters

Beyond that, I do not know how to solve it.
Thank you.
 
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Sounds like you have a little geometry problem. Don't you just need to find the point away from the mid-line whose distance from each speaker is different by half a wavelength?
 

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