Solving BVP with Analytical Solution in (0,1)^2

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SUMMARY

This discussion focuses on solving a boundary value problem (BVP) defined in the domain (0,1)^2, governed by the equation -u_{xx} - u_{yy} = 0. The analytical solution is given as u(x,y) = θ, with boundary conditions needing clarification. The boundary conditions identified include u = 0 on y = 0, u = π/2 on x = 0, u = arctan(y) on x = 1, and u = arctan(x^{-1}) on y = 1. The transformation to cylindrical polar coordinates is suggested for further analysis.

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TL;DR
How to determine the boundary conditions to this elliptic BVP given an analytical solution
For this BVP in ##(0,1)^2##,
$$
-u_{xx} - u_{yy} = 0
$$
subject to some boundary data it is said the analytical solution is ##u(x,y) = \theta##. I've thought about this for awhile I can't seem to figure out how to determine the boundary conditions for this BVP. Moreover, ##\theta## is illustrated in figure attached. Some comments would be greatly appreciated.
 

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In polar coordinates, x = r \cos \theta \qquad y = r \sin \theta. Since you're in the first quadrant both x and y are positive, so you don't lose any information by dividing: <br /> \frac yx = \tan \theta.
 
Thank you for the reply. However, given that I am also trying to also solve this numerically, I was curious what BCs I would need to satisfy the equations? This is my main concern.
 
The question is given that ##u=\theta## is the solution to the differential equation given unknown boundary conditions, what must those unknown boundary conditions be?

It's stupidly obvious actually, the boundary condition must be ##u=\theta## on the boundary. I feel like I must not understand the question right.
 
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Substitute into the given equation: u = 0 on y = 0, u = \pi/2 on x = 0, u = \arctan(y) on x = 1, and u = \arctan(x^{-1}) on y = 1.
 
Transform the differential equation (Laplace's equation) to cylindrical polar coordinates and see what it says.
 

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