- #1

Raysi25

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## Homework Statement

Car A (m1=1405kg) crashes into Car B (m2=873kg) which is stationary and perpendicular to Car A. Car B is moved a distance of 1.8m out of the way and Car A rolls to a stop 9.6m away at 1.93 m/s. Assuming the coefficient of friction is 0.8, can the velocity of Car A be calculated before impact?

Please see amazing diagram attached for a clear depiction of crash.

Variables:

m1=1405kg

m2=873kg

v1=?

v2=0m/s

µ=0.8

d=1.8m

## Homework Equations

W=F*d

F=µmg

## The Attempt at a Solution

Force required to move Car B

F=µmg

= 0.8*873*9.8

= 6844N

Work done to move Car B

W=F*d

= 6844 * 1.8

= 12,320J

Not sure where to go from here...can anyone please point me in the right direction?

#### Attachments

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