Car Crash Problem: Solving Speed Before Impact

In summary: To find the kinetic energy after the collision, use the equation for momentum: (M+m)vf = MviFrom there, the energy equation is mμgs = (M+m)vf2/2Combining these:vi2 = 2(M+m)mμgs/M2which gives vi = 4.1m/s. Did you brake at any point during this? If so, approximately when?In summary, the car was traveling at an unknown speed and hit a metal box. The box moved 1m and the car had kinetic energy of 7,828.38J.
  • #1
ryantosi
4
0
**Not a homework problem but I was directed here**

Hello, over the weekend I was involved in a car accident and received a careless driving ticket because the officer believed that I was going an insane amount of speed. My first instinct to react to this would to be to sit down and do the physics behind it. Now I know that the physics I have used here is not going to be 100% precise as I have not factored in the crumple zone of the car, or how much hitting the curb had slowed me down. However, I am just trying to get a general idea of how fast I truly hit the box. I have not taken physics for over a year and a half now so I am a bit rusty so please bear with me.

A 1590kg car is traveling at an unknown speed. It hits a 1140kg metal box sitting on concreate which is not bolted down. If the box moves 1m, how fast was the car traveling right before impact. Based on my research I have found that the coefficient of friction of steel on concrete varies between 0.45 and 0.7, let's use 0.7 for the benefit of the doubt. Correct me if I'm wrong on this but this would be how i would go about this equation:

Normal force of box=Frictional force=MA=(1140kg)(9.81m/s^2)=11,183.4N
W=FDµ (11,183.4N)(1m)(0.7)= 7,828.38J

Ekinitial=Ekfinal (0.5)(M)(V)^2=7,828.38J V=√((2)(7828.38J))/(1590kg)

The speed of the car before the crash is 3.14m/s
1m/s=3.6km/h (3.14m/s)(3.6)= 11.3km/h
 
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  • #2
Use enrgy conservation.
The box moved 1m. How much frictional energy dissipation does that represent, assuming mu_k = 0.7 and mass = 1140 kg?

Then equate that to the k.e. of the car just before impact.
 
  • #3
Sorry what? I've only just finished physics 30 and don't understand how to factor in frictional energy dissipation. As for relating that to the kinetic energy of the car-box that is what I had done.
 
  • #4
An interesting situation, I'm not sure any physics will do you well here but anyways...

You need to consider both kinetic and static friction, but assuming just kinetic for now (actually about 0.4 from what I hear)

[itex] F_{fk} = μ_{k} F_{N} = μ_{k} mg = 4473.36\;N[/itex]

[itex] W = Fxcosθ = Fx = 4476.36\;J[/itex]

By the work energy theorem and final speed is zero:

[itex] W = ΔK = \frac{1}{2}m(v_{f}-v_{i}) = \frac{1}{2}mv_{i} [/itex]

[itex] v_{i} = \frac{2W}{m} = 5.63 \; \frac{m}{s} = 12.6 \frac {mi}{hr}[/itex]From what I think, you could account for static friction by conservation of momentum, but that would require an estimate of the speed of the concrete block immediately after you hit it.
 
  • #5
You need to consider it in two stages. First, there's the collision with the box. Your car is designed to crumple to absorb the impact, so this is almost entirely inelastic. So for this part use conservation of momentum:
(M+m)vf = Mvi
From there, the energy equation is mμgs = (M+m)vf2/2
Combining these:
vi2 = 2(M+m)mμgs/M2
which gives vi = 4.1m/s.
However, this assumes you made no attempt to brake, which might also be considered careless driving. Did you? If so, approximately when?
 
  • #6
Sentin31 reflects what I tried to say. That's energy conservation.

Momentum conservation does not work since upon impact some of the momentum of your car was transferred not only to the box but to the Earth due to static friction.
 
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  • #7
rude man said:
Sentin31 reflects what I tried to say. That's energy conservation.

Momentum conservation does not work since upon impact some of the momentum of your car was transferred not only to the box but to the Earth due to static friction.
No, you have to consider two separate phases: the collision itself, where momentum is conserved but there's an unknown loss of kinetic energy, and the subsequent slide. Since you know the distance and force in the slide you can use energy for that phase.
 

Related to Car Crash Problem: Solving Speed Before Impact

1. What is the "car crash problem"?

The "car crash problem" refers to the situation where a car is about to collide with another object or vehicle, and the driver needs to determine the speed necessary to avoid impact.

2. Why is solving speed before impact important in a car crash?

Knowing the necessary speed to avoid impact is crucial in preventing or minimizing the severity of a car crash. It can also help determine fault and liability in the event of an accident.

3. How do scientists calculate the necessary speed to avoid impact?

Scientists use equations from physics, such as the Kinematic Equations, to calculate the necessary speed before impact. They take into account factors such as distance, time, and acceleration to determine the required velocity for the car to avoid collision.

4. What other factors besides speed can affect the outcome of a car crash?

Other factors that can affect the outcome of a car crash include the weight of the vehicles, the angle of impact, the road conditions, and the use of safety features such as seatbelts and airbags.

5. Can technology play a role in solving the speed before impact problem?

Yes, technology such as radar sensors and automatic braking systems can assist drivers in determining the necessary speed to avoid impact. These advanced safety features can help prevent accidents and save lives on the road.

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