Solving Cloud Physics Problems - Brad's Request for Help

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The discussion revolves around two cloud physics problems posed by a user named Brad. The first problem involves calculating the number of water droplets in a cloud needed to produce 0.5 cm of rainfall, with the expected answer being 1 x 10^21 droplets. The second problem requires determining the dimensions of constants A and h in a force equation related to mass and distance. Participants suggest that the volume of the droplets must equal the volume of the rainfall, and emphasize that the argument of the exponential in the force equation must be dimensionless. The conversation highlights the complexity of these physics concepts, noting that they may be more advanced than typical high school curriculum.
brad sue
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Hi I have those 2 problems:

A typical cloud contains droplets of water with an average radius of .5 * 10^-4m.
how many droplets are needed for a cloud that provides a rainfall of .5 cm.
( the answer must be 1*10^21 droplets)


for this second problem I don't know how to find two equations:

A force F acting on a body of mass m a distance r from some origin has a magnitude of F=(A*m*exp(h*r))/r^4, where A and h are both constants.
Given that the force has dimensions kilogram-meter per seconds squared, what are the dimensions of both A and h.

Please can I have some help or suggestions for those problems?

Thank you very much

brad
 
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(a) N = \frac{3 A h}{4 \pi r^3}

where A is the area to be covered, h = 0.5 cm is the depth and r is the radius of each drop.

(b) Hint: the argument of the exponential must be dimensionless - and - the dimensions of mA must be that of the force.
 
Last edited:
Yeah (b) shouldn't be a problem...

But what is (a)??

Granted I'm in high school but I've never encountered that kind of physics... where does it come from?
 
It is college physics freshman
but I am sure U can do it :smile:

I have no idea how Tide find the solution for the first problem ( N=...)
I will try to work on it but if I don't find something I will ask him how he did it.
Thanks

brad

HiPPiE said:
Yeah (b) shouldn't be a problem...

But what is (a)??

Granted I'm in high school but I've never encountered that kind of physics... where does it come from?
 
The total volume of the drops (number of drops times the volume of each drop) is equal to the volume of the fallen rain (depth of rainfall times the area covered by the rain).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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