Solving Cylinder Volume from Rectangle Perimeter of 40cm

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Homework Help Overview

The problem involves a rectangle with a perimeter of 40 cm that is rotated around one of its sides to form a right cylinder. The goal is to determine the largest possible volume for this cylinder, which has led to various calculations and interpretations of the relationships between the dimensions of the rectangle and the resulting cylinder.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equations derived from the perimeter and volume formulas, with one participant attempting to derive the maximum volume using calculus. There is also a question regarding the correct interpretation of the perimeter equation, with suggestions that it may need to account for diameters instead of radii.

Discussion Status

The discussion includes attempts to clarify the calculations and assumptions made regarding the dimensions of the rectangle and the resulting cylinder. Some participants have offered corrections to the original equations, while others have raised questions about the appropriateness of the perimeter equation used. There is a mix of understanding and confusion, with some participants expressing appreciation for the guidance provided.

Contextual Notes

Participants are navigating through the constraints of the problem, including the fixed perimeter and the implications of rotating the rectangle around one of its sides. There is a noted confusion about whether the radius or diameter should be used in the calculations, which affects the derived equations and results.

danizh
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Question: A rectangle with a perimeter of 40cm is rotated around one of its sides, creating a right cylinder. What is the largest possible volume for this cylinder?
Here's what I have done so far:
Equation #1:
40 = 2h + 2r
r = 20 - h
Equation #2:
Volume = pi*r^2h
= pi(20-h)(h)
= 20pi*h - h^2*(pi)
Derivate of volume: 20pi-2pi*h
10=h
Therefore, r also equals 10.
Thus, the maximum volume is 3141.592cm^3, which is incorrect.
The actual answer is 3723.37cm^3. Any help would be great. :biggrin:

Sorry, but I think this should be in the "Calculus and Beyond" board.
I'm not too sure how to move it there, though.
 
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danizh said:
Equation #2:
Volume = pi*r^2h
= pi(20-h)(h)
= 20pi*h - h^2*(pi)
I think you forgot to square the radius (20-h) when putting it in...

I may be wrong, I just looked at it quickly and that's what I saw.

EDIT: My way, my calculator now tells me 3723.3691 so yup, that was your mistake
 
Last edited:
Thanks for the help, I really appreciate it.
I'll be more careful next time. :smile:
 
I have another question, wouldn't it be more appropriate if the "restraint equation" was 40 = 2h + 4r rather than 40 = 2h + 2r. It just seems to make more sense since if the cylinder is transformed into a rectangle, each side of the triangle would be a diameter (or two times the radius) rather than just the radius, which we are assuming right now. I'm just curious to know why I get the wrong answer if I do it the way that seems to be more logical to me.
 
danizh said:
I have another question, wouldn't it be more appropriate if the "restraint equation" was 40 = 2h + 4r rather than 40 = 2h + 2r. It just seems to make more sense since if the cylinder is transformed into a rectangle, each side of the triangle[\b] would be a diameter (or two times the radius) rather than just the radius, which we are assuming right now. I'm just curious to know why I get the wrong answer if I do it the way that seems to be more logical to me.


I assume you meant "rectangle" where you wrote "triangle" above. The reason a side of the rectangle is a radius not a diameter is that the rectangle is rotated about one side, not about a center line of the rectangle.
 
Ah, I understand it now! Thanks for clearing that up.
I think the key to the question is that it is rotated to create a right cylinder.
 
what did you get for your "r" value? I'm doing somethign wrong...
 

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