Solving Delta Function Convolution with Sin Wave

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SUMMARY

The discussion focuses on solving the convolution of a delta function, represented as f1(t) = δ(t) + δ(t-2), with a sine wave f2(t) = sin(πt) within the limits of integration from 0 to 2. The key insight provided is the application of the sampling property of the delta function, which simplifies the convolution integral significantly. The convolution of a function with a delta function results in the function being evaluated at the points where the delta functions are located, leading to the conclusion that the convolution results in two impulses at x=0 and x=2.

PREREQUISITES
  • Understanding of convolution in linear time-invariant systems
  • Familiarity with delta functions and their properties
  • Knowledge of sine wave functions and their mathematical representation
  • Basic calculus skills for evaluating integrals
NEXT STEPS
  • Study the properties of the Dirac delta function in detail
  • Learn about convolution integrals in linear systems
  • Explore the sampling property of delta functions
  • Practice solving convolution problems involving different functions
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Students and professionals in signal processing, electrical engineering, and applied mathematics who are working with linear time-invariant systems and convolution operations.

error 401
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hi

I really need your help ...

for linear time invariant system

f(t) =f1(t) (convolution) f2(t)
f(t) = ∫f1(t).f2 ( t-T)
or f(t) = ∫f1(t-T).f2(t)

where f1(t) = delta function = δ(t).δ(t-2)
and f2(t) = sine wave = sin ( ∏t )

how i can solve this ... my problem is : how can i make this integration with impulse ??


thanks in advance
 
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i forget that ... the limits of integration from (0 ) to (2)
 
error 401 said:
hi

I really need your help ...

for linear time invariant system

f(t) =f1(t) (convolution) f2(t)
f(t) = ∫f1(t).f2 ( t-T)
or f(t) = ∫f1(t-T).f2(t)

where f1(t) = delta function = δ(t).δ(t-2)
and f2(t) = sine wave = sin ( ∏t )

how i can solve this ... my problem is : how can i make this integration with impulse ??


thanks in advance

First, you need to get your convolution integral right.
Then, what do you mean by " f1(t) = delta function = δ(t).δ(t-2) "? It's not an equation I can make sense of ...
 
rude man said:
First, you need to get your convolution integral right.
Then, what do you mean by " f1(t) = delta function = δ(t).δ(t-2) "? It's not an equation I can make sense of ...

i mean how can i solve this integral

∫δ(t).δ(t-2)sin(∏t)
 
\delta(t)\delta(t-2) = 0

And the convolution of a function with zero is zero. Your definition of the convolution integral appears incorrect. I suspect you are not giving us all the details, because the problem makes no sense. What was the original problem? (I know there was one since the limits of integration have already simplified from -inf to inf to 0 to 2)

edit:
I'll go ahead and throw out a property that may be helpful, though what you've given us so far doesn't indicate you will use it. The sampling property states

\int\limits_{a}^{b}\delta(x-c)f(x)dx=f(c)

if b > c > a

This property leads to a very simple result when convolving some function f(t) with an impulse d(t - c).
 
Last edited:
the original problem is : convolution between 2 function ( sine wave and delta function ) but when he sketch delta function ..gives two vertical lines ..one of them at x=0 upward and the other at x=2 downward ...

so how can i solve this ?!

and I really appreciate your assistance :)
 
error 401 said:
the original problem is : convolution between 2 function ( sine wave and delta function ) but when he sketch delta function ..gives two vertical lines ..one of them at x=0 upward and the other at x=2 downward ...

so how can i solve this ?!

and I really appreciate your assistance :)

That is just the sum of two Dirac delta functions.

f_1(x) = \delta(x) + \delta(x-2)

Just write out the convolution integral and use the sampling rule.
 
:D

thank you so much ..
 

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