Solving Diff Eqns: Renaming Constants & Reversing Signs

  • Context: Graduate 
  • Thread starter Thread starter Joseph1739
  • Start date Start date
  • Tags Tags
    Constants
Click For Summary
SUMMARY

This discussion focuses on the manipulation of constants in the context of solving differential equations, specifically when renaming and negating constants. The initial condition is given as Q(0) = Q0, leading to the equation -ln|25-Q| + c1 = rt/100 + c2. Participants clarify that while combining constants allows for renaming, negating a constant and renaming it requires careful attention to sign changes. The correct interpretation shows that if -c = C, then C = 25 - Q0, aligning with the original equation's structure.

PREREQUISITES
  • Understanding of differential equations and their solutions
  • Familiarity with logarithmic functions and properties
  • Basic algebraic manipulation skills
  • Knowledge of initial conditions in differential equations
NEXT STEPS
  • Study the properties of logarithms in differential equations
  • Learn about the method of integrating factors in solving differential equations
  • Explore the implications of constant renaming in mathematical proofs
  • Review examples of initial value problems in differential equations
USEFUL FOR

Mathematics students, educators, and anyone involved in solving or teaching differential equations will benefit from this discussion, particularly those interested in the nuances of constant manipulation.

Joseph1739
Messages
33
Reaction score
0
Suppose I'm at this point in solving a differential equation and the initial condition is Q(0) = Q0
-ln|25-Q| + c1 = rt/100 + c2
Then if I combine c2-c1, I can rename it to c, we have:
-ln|25-Q| = rt/100 + c
Now if I multiply the equation by (-1), I get:
ln|25-Q| = -rt/100 - c
If I let -c = C:
ln|25-Q| -rt/100 +C

But if I rewrite -c = C, all the signs are reversed when I solve for Q. Also solving for the constant, my book kept the -c, and got c = Q0-25, but when I rewrite -c to C, I get C = 25-Q0.

So my question is, when can I rename constants? When I combined two constants it is okay to to rename the constant, but why is it incorrect when I negate a constant and rename it?
 
Physics news on Phys.org
Joseph1739 said:
Suppose I'm at this point in solving a differential equation and the initial condition is Q(0) = Q0
-ln|25-Q| + c1 = rt/100 + c2
You can simplify things a bit by including the constant only on one side (the right side).

Joseph1739 said:
Then if I combine c2-c1, I can rename it to c, we have:
-ln|25-Q| = rt/100 + c
Now if I multiply the equation by (-1), I get:
ln|25-Q| = -rt/100 - c
If I let -c = C:
ln|25-Q| -rt/100 +C
You lost an = in the line above.
Joseph1739 said:
But if I rewrite -c = C, all the signs are reversed when I solve for Q. Also solving for the constant, my book kept the -c, and got c = Q0-25, but when I rewrite -c to C, I get C = 25-Q0.

So my question is, when can I rename constants?
Whenever you want to.
Joseph1739 said:
When I combined two constants it is okay to to rename the constant, but why is it incorrect when I negate a constant and rename it?
If -c = C, and the book shows c = ##Q_0 - 25##, then C = ##-(Q_0 - 25) = 25 - Q_0##.
 
Joseph1739 said:
Suppose I'm at this point in solving a differential equation and the initial condition is Q(0) = Q0
-ln|25-Q| + c1 = rt/100 + c2
Then if I combine c2-c1, I can rename it to c, we have:
-ln|25-Q| = rt/100 + c
Now if I multiply the equation by (-1), I get:
ln|25-Q| = -rt/100 - c
If I let -c = C:
ln|25-Q| -rt/100 +C

But if I rewrite -c = C, all the signs are reversed when I solve for Q. Also solving for the constant, my book kept the -c, and got c = Q0-25, but when I rewrite -c to C, I get C = 25-Q0.

So my question is, when can I rename constants? When I combined two constants it is okay to to rename the constant, but why is it incorrect when I negate a constant and rename it?

Check your math. Your calculation of c and -C are wrong.

Looking at your last 2 equations, at t=0 you either get ln\left|25-Q_0 \right| = -c or ln\left|25-Q_0 \right| = C. These two results agree with your definition c=-C.

You can always define a new constant as a combination of multiple constants.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
18
Views
4K
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K