- #1

alseth

- 15

- 0

dy/dx=(2x+y-3)^(1/2)

i tried to do some substitution

v=2x+y-3

then

dv/dx=2+dy/dx

dy/dx=dv/dx-2

then i substituted back into original equation

dv/dx-2=v^(1/2)

dv/(v^(1/2)+2)=dx

integrated and got something like this

2v^(1/2)-4ln(v^(1/2)+2)=x+c

i do not know whether this is the correct method and what to do with 2v^(1/2)-4ln(v^(1/2)+2)=x+c

thanks for the advice