Solving differential equations for steady state

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sozener1
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a) when I put dw/dt = 0 I get something like e^(b/a) is this correct?
 
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  • Text problem 2 on the modified logistic equation dw/dt = w(b - a log w) for tumour growth in mice, with parts (a) to (c) and given values a = 1/25, b = 2/5.
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sozener1 said:
from the attachment

a) when I put dw/dt = 0 I get something like e^(b/a) is this correct?

Do not post thumbnails; they are unreadable on some media. Just type out the problem. (See the 'pinned' post 'Guidelines for students and helpers', by Vela, which explains the reasons behind this standard.)