Solving Differential Equation with Frequency Response

Click For Summary

Homework Help Overview

The discussion revolves around solving a differential equation that models the AC response of an inductor, specifically in the context of finding the current when a sinusoidal voltage is applied. The equation in question is L di/dt + iR = V, with V defined as V_0 sin(ωt).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correctness of a proposed solution, with one original poster sharing their final form of the current. Others express difficulty in assessing the solution due to an unreadable image and suggest using LaTeX for clarity. There is mention of needing to consider the general solution alongside the particular solution.

Discussion Status

The discussion is ongoing, with some participants providing helpful tips for formatting and clarity. There is acknowledgment of the correctness of the particular solution, but a reminder that the general solution should also be addressed. The conversation reflects a collaborative effort to ensure understanding and correctness.

Contextual Notes

Participants are encouraged to check the correctness of their solutions by substituting them back into the differential equation. There is an emphasis on the importance of including both particular and general solutions in the context of the problem.

Master1022
Messages
590
Reaction score
116

Homework Statement


The AC response of an inductor can be modeled by the following differential equation:
L \frac{di}{dt} + iR = V

Find, using frequency response, the current of the system when the applied voltage V is: V = V_0 \sin(\omega t)

Homework Equations

The Attempt at a Solution


In the attached photo. Does this seem to be correct?

The final form comes out as:
I(t) = \frac{V_0}{R^2 + L^2\omega^2} [R\sin(\omega t) - \omega L \cos(\omega t)]
 

Attachments

  • IMG_5670-2.JPG
    IMG_5670-2.JPG
    38.2 KB · Views: 442
Last edited:
Physics news on Phys.org
Master1022 said:

Homework Statement


The AC response of an inductor can be modeled by the following differential equation:
L \frac{di}{dt} + iR = V

Find, using frequency response, the current of the system when the applied voltage V is: V = V_0 sin(\omega t)

Homework Equations

The Attempt at a Solution


In the attached photo. Does this seem to be correct?

Your posted image is unreadable on my devices, so there is no way I could judge correctness. Please type out at least the final form of your solution. Doing this should be relatively straightforward using LaTex. But please remember to NOT type "sin" in LaTeX: type "\sin" instead to get much more readable results (##\sin \theta## instead of ##sin \theta,## etc) . The same holds for most other functions: all the trig and inverse trig fcns, the logarithms "\ln" and "\log", as well as "lim", "max", "min", "sup", "inf", plus the hyperbolic fcns, etc.
 
Ray Vickson said:
Your posted image is unreadable on my devices, so there is no way I could judge correctness. Please type out at least the final form of your solution.

Thanks for the tips. Have put the final form there now.
 
Master1022 said:
Thanks for the tips. Have put the final form there now.

Yes, your final form is correct for a particular solution, but the general solution needs the addition of a solution to the homogeneous DE (which dies away to zero exponentially for large ##t>0##.)

Checking for correctness of a solution can always be done by plugging it into the DE to see if it works. That is something that should always be done; that used to be a tedious procedure, but nowadays we can use a computer algebra system to do all the work.
 

Similar threads

Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
8
Views
1K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
951
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K