Finding an Integrating Factor for Solving Differential Equations

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Homework Help Overview

The discussion revolves around finding an integrating factor for the differential equation given in the form y(x+y)dx+(xy+1)dy=0. Participants are exploring the concept of integrating factors in the context of differential equations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive an integrating factor and are expressing confusion about the integration process and the dependence of variables. There are questions regarding the formulation of the integrating factor and its relation to the variables involved.

Discussion Status

Some participants have offered observations about the formulation of the integrating factor, noting inconsistencies in variable dependencies. There is an ongoing exploration of the necessary steps to achieve an exact form of the differential equation.

Contextual Notes

Participants have mentioned challenges with integration skills and the use of specific notation in their attempts. There is an acknowledgment of the need for clarity in the setup of the integrating factor.

Phatman
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1. solve the problem first finding an integrating factor of susceptible form.
y(x+y)dx+(xy+1)dy=0

Homework Equations


form: M(x,y)dx+N(x,y)dy=0
intigrating factor: eint(1/n(dm/dy-dndx)dx

The Attempt at a Solution


u(x)=eint(1/(xy+1)(y(x+y)d/dy-(xy+1)d/dx)dx
this reduces to
eint((x+y)/(xy+1))dx

This is where I need help. my integration is not good. I know that if I can solve for the integrating factor then I can solve for the equation because it will be in exact form.

Thanks for any help.
 
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Phatman said:
1. solve the problem first finding an integrating factor of susceptible form.
y(x+y)dx+(xy+1)dy=0

Homework Equations


form: M(x,y)dx+N(x,y)dy=0
intigrating factor: eint(1/n(dm/dy-dndx)dx

The Attempt at a Solution


u(x)=eint(1/(xy+1)(y(x+y)d/dy-(xy+1)d/dx)dx
This makes no sense to me. Your integrand is a function of x and y but you are integrating with respect to x so the exponent will be a function of y only yet you say that equals a function of x!

this reduces to
eint((x+y)/(xy+1))dx

This is where I need help. my integration is not good. I know that if I can solve for the integrating factor then I can solve for the equation because it will be in exact form.

Thanks for any help.
 
Phatman said:
1. solve the problem first finding an integrating factor of susceptible form.
y(x+y)dx+(xy+1)dy=0

Homework Equations


form: M(x,y)dx+N(x,y)dy=0
intigrating factor:
inigrating factor.jpg


The Attempt at a Solution

( Please excuse the u(x) remnants I'm leaning how to use the white boar editor.)[/B]
inigrating factor#2.jpg

this reduces to ( Please excuse the u(x) reminets I'm leaning how to use the white boar editor.)
inigrating factor#3.jpg


This is where I need help. my integration is not good. I know that if I can solve for the integrating factor then I can solve for the equation because it will be in exact form.

Thanks for any help.
edited to make it easier to read
 
Halsofivy, you are right u(x) should be in terms of x. the way it works out in the book examples is y gets factored out while solving for the intigal. leaving only a function of x.
 

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