Solving Diffusion Problem Homework Statement

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The discussion focuses on solving a diffusion problem related to steady state concentration and the balance of fluxes due to diffusion and potential. The steady state concentration is defined as the concentration as time approaches infinity, but the initial concentration c(x, 0) is unknown. Participants discuss the equations for flux, with diffusion represented as D(dc/dx) and potential possibly represented as ax^2. To find the solution, it's suggested to convert potential into a force by taking the gradient and equating it with the diffusion force. The conversation also references Einstein's work on Brownian motion and its application to atmospheric density calculations.
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Homework Statement



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2. The attempt at a solution

a) The steady state concentration is the concentration when t --> infitine, right? How can I find that when I don't know c(x, 0)?
 
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You have two fluxes, one due to diffusion, the other due to the potential. In steady state, these cancel each other. So try writing those equations down and solving them.
 
Flux due to diffusion = D\frac{dc}{dx}, right?

How about the flux due to the potential? Is that simply ax^2?

It that is true, I get c=\frac{a}{3D}x^3

I still don't know what to do with b) and c) though...
 
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No, you need to convert the potential into a force. You do that by taking the gradient.

Now is it the case that D\frac{dc}{dx} is a force? If it is, then maybe the next step would be to set these forces equal, diffusion and that from the potential. As far as getting a force from diffusion, would that have something to do with "pressure"? I hope there is something in your text or notes that will further you on this.

By the way, I think Einstein was the one who originally solved this question for Brownian motion. One of the applications is to calculate the density of the Earth's atmosphere as a function of altitude. In this case, the potential is due to gravity, which is balanced against diffusion. (I.e. that's why we can breathe at even high altitude places a couple miles above the lowest points on the planet.) Here's an article:
http://psas.pdx.edu/RocketScience/PressureAltitude_Derived.pdf
 
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