Solving Direction of Current Homework Equation

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SUMMARY

The discussion revolves around determining the positive terminal of a battery in a magnetic field scenario involving a hanging mass. The participant initially calculated the current direction using the equation F = Il X B, concluding that the positive terminal is on side b of the battery. However, after applying the right-hand rule, they corrected their understanding, concluding that the current flows to the right, indicating that side a is the positive terminal. The confusion stemmed from incorrect application of the cross product in their initial calculations.

PREREQUISITES
  • Understanding of magnetic fields and forces, specifically F = Il X B.
  • Familiarity with the right-hand rule for determining current direction.
  • Basic knowledge of electric circuits and battery terminals.
  • Proficiency in vector cross products and their applications in physics.
NEXT STEPS
  • Review the right-hand rule and its applications in electromagnetism.
  • Study vector cross products in detail, focusing on their geometric interpretation.
  • Explore magnetic force calculations in various configurations using F = Il X B.
  • Practice problems involving current direction and magnetic fields to reinforce understanding.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to improve their understanding of magnetic forces and current direction in circuits.

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Homework Statement


the mass is hanging from the bar. the magnetic field points into the page. The magnetic force is the only thing supporting the bar (negligible mass) and the weight. What side of the battery, a or b, has the positive terminal of the battery?

attachment.php?attachmentid=16825&d=1229135040.jpg

Homework Equations


F = Il X B

The Attempt at a Solution



I tried this 2 different ways and keep getting a different answer than what my professor has.
since the magnetic field goes into the page i have:
B = -j
the force goes up, so i have that as
F = k
i considered left to right to be (+i)
so then i have the equation:
F = Il X B
or
k = I X (-j)
where I = (-i) direction, meaning I goes from right to left on the bar. this would mean that the positive terminal is on the b side of the battery. Am I doing this wrong? or does the professor have the wrong answer?edit: i must be doing something wrong. I am goin through all my homework and i seem to be getting the wrong direction on every question. can somebody walk me through how to find the answer to this?

edit2: ok well i was about to panick but now that i can do the right hand rule (which was a lot easier than i thought it was) I am getting all my directions right. but I am still curious to know what I am doing wrong with my cross products. I am not sure why they're all wrong.
 

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I can't see your diagram, but assuming that the arrangement is like this

B
x x x x

x x x x
a ----------b
I

then the current must be flowing to the right (just use the right-hand rule) which implies that a is positive.
 

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