Solving Dynamics-Friction for Max θ w/ μ_s=0.25

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SUMMARY

The discussion focuses on calculating the maximum angle θ at which a box can rest on a ramp without slipping, given a static friction coefficient μ_s of 0.25. The equations derived include F_x = ma_x and μ_sη - mg sin(θ) = ma_x, leading to the conclusion that the acceleration a_x is zero at the maximum angle. This indicates that the forces acting on the box are balanced, allowing for the determination of θ using the relationship between friction and gravitational forces.

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Homework Statement



A box is halfway up a ramp. The ramp makes an angle, θ with the ground. What is the maximum value of θ before the mass will slip? μ_{s}=0.25

Homework Equations



F_{x}=ma_{x}

The Attempt at a Solution


I drew a free body diagram to show the forces affecting the box

η-mgcos=0
η=mgcosθ (eq'n 1)
F_{x}=ma_{x}
μ_{s}η-mgsinθ=ma_{x} (sub eq'n 1 in)
μ_{s}(mgcosθ)-mgsinθ=ma_{x}
mg(μ_{s}cosθ-sinθ)=ma_{x}


I'm not sure where to go from here, or even if this is the correct path for me to take
 
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Your equations are correct.

The question has essentially asked you to calculate max value of (theta), so the block does not slip. What does that tell you?...Acceleration is 0. Now you know what to do.
 

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