Solving Dynamics Homework: Frictionless Ramp & 5.0kg Block

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SUMMARY

The discussion focuses on a physics problem involving a flat-bed truck with a frictionless ramp and a 5.0kg block. The truck accelerates forward, causing the block to remain stationary relative to the ramp. The key equations used include F=ma and Ffriction=Fnormal*mew, leading to the calculation of the force exerted by the truck's engine, which is determined to be 11760 Newtons due to a rolling coefficient of friction of 0.10.

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  • Understanding of Newton's laws of motion
  • Knowledge of friction coefficients and their application
  • Familiarity with basic kinematics and acceleration calculations
  • Ability to apply trigonometric principles to physics problems
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  • Learn about inclined plane dynamics and forces
  • Explore advanced applications of F=ma in real-world scenarios
  • Investigate the role of acceleration in non-inertial reference frames
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their understanding of dynamics and friction in motion.

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Homework Statement


A flat-bed truck with a frictionless ramp accelerates forward.


/l (That 35 is the angle, and a 5kg block rests on the hypotenuse)
--- / l
- - /35 l
- ---------------
-----------------
-o-----------0--

The acceleration of the truck is suck that a 5.0kg block is stationary (relative to the ramp). If the rolling coefficient of friction is (mew=0.10) Find the force the engine is exerting on the 12000kg truck.


Homework Equations


F=ma, Ffriction=Fnormal*mew


The Attempt at a Solution


I found the block accelerates 9.8m/s^2 downwards and 13.98m/s^2 to the left, ant the total acceration is 17.1m/s^2
 
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I found the force of friction on the truck (12000*9.8*0.1) to be 11760Netwons.
 
Please help me :'(
 

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