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QuickSkope

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## Homework Statement

A car is moving at an acceleration such that a 5kg block in the back of the remains still on a ramp at 35*. The ramp is frictionless, whereas the coefficient of friction between the truck and the road is μ=0.1. If the truck weighs 12000kg, what is the force the trucks engine is exerting?

## Homework Equations

Dynamics formula

Fnet Formulas

## The Attempt at a Solution

We know that the Ramp only has Force Parrallel pushing it down.

Parrallel= mgSinθ

= (9.8)(5)(Sin35)

=28.105

We also know that the only thing that would push the block UP the ramp is the Fnet of the truck. For the Block to remain still, it has to have an Fnet of 0. Since its on a Ramp, you have to find the Fx.

Fx= Cos35*28.105 = 23.02.

From there, we know the Fnet of the truck is 23.02.

Fnet = Fa - Ff

23.02= Fa - (0.1)(9.8)(12000)

Fa = 11783.02

Does that seem right? I feel like it is a little bit off. Any help would be much appriciated.