Solving Dynamics Problem: Boat Mass m, Velocity v0, Friction Force Fd

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Homework Help Overview

The problem involves a dynamics scenario where a boat with a specified mass is decelerating due to a frictional force that is proportional to its velocity. The objective is to determine the time required for the boat to reduce its speed from an initial velocity to a specified final velocity.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the integration of acceleration as a function of velocity and the challenges of expressing acceleration in terms of time. There are attempts to derive a differential equation using Newton's second law and to solve for velocity as a function of time.

Discussion Status

Several participants have offered guidance on setting up the problem, including suggestions for integrating the equations. There is ongoing exploration of the correct application of initial conditions and integration constants, with some participants expressing uncertainty about their calculations and results.

Contextual Notes

There is a noted correction in the initial and final velocities provided by one participant, which may affect the calculations being discussed. The participants are also navigating the implications of non-constant acceleration in their approaches.

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Homework Statement



A boat has mass m=1000 kg and is moving at velocity v0=324 ms^-1. Friction force btw the boat and water is proportional to velocity v, Fd=70*v. How long it takes to slow down to 162ms^-1 ?


Homework Equations


I'm not sure which function should I integrate, because acceleration is not constant.


The Attempt at a Solution


I understand Friction force and acceleration as functions of v, but I have no idea how to express these as functions of time, since acc is not constant. Then I would integrate a(t) with respect to time and substitute final velocity for v(t) and from that I'd get the answer.
 
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Draw a force diagram, and apply Newton's 2nd law. You can get the acceleration that way. Then use a = \frac{dv}{dt} to get a differential equation. Solve it and find v in terms of t. Solve for t and substitute correct value of v to find the time.
 
a=-70v/m
∫dv=∫(-70v/m)dt
v=-70/m ∫vdt - the problem is I do not know v in terms of t :(
 
Instead of your second line, do this,
\int{\frac{dv}{v}}=\int{\frac{-70 dt}{m}}
 
I have to correct given informtion v0=25 ms^-1 and v=12.5 ms^-1

Ok, I tried your suggestion and from that I get:

t = (-m*(ln(v) + v0))/70 -what doesn't seem right

After substituting v = 12.5 I get t = 393 s and that is wrong (correct answer should be 9.9s)
 
rammer said:
t = (-m*(ln(v) + v0))/70
This does not agree with my final answer.

Check whether you applied the initial boundary condition (v = v0 when t=0 ) correctly.
 
At t = 0, I'm pretty sure, the integration constant is equal vo (=25).
 
Not ln(vo) ?
 
Yes, you're right, thanks. I finally got it correct. My mistake was I put the constant directly from initial conditions, not solving from integrated function.
 

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