Solving Equations: Choosing the Right Method | Homogeneous Equation Example

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Homework Help Overview

The discussion revolves around solving two equations: a differential equation involving variables t and y, and another homogeneous equation relating dy/dx to a function of x. Participants are exploring methods for solving these equations and verifying their approaches.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss separating variables as a method for the first equation and share their integration results. Questions arise regarding the correctness of the derived expressions and the methods used. For the second equation, there is uncertainty about the approach and the solutions obtained.

Discussion Status

There is an ongoing exchange of methods and results, with participants seeking confirmation on their calculations and interpretations. Some guidance has been offered regarding the separation of variables, but there is no explicit consensus on the correctness of the solutions presented.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct assistance they can provide to each other. There is also a noted confusion regarding the second equation, indicating a need for further clarification.

Dao Tuat
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Could someone help me out and tell me what method to use to solve:

(t^3)(y^2)dt + (t&4)(y^-6)dy = 0

Also, the equation dy/dx - y/x = (x^2)sin2x is homogeneous, right?

Thanks,
Dao Tuat
 
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for the top one try seperating the variables
 
Ok, so I separated them and integrated and ended up with:
y=[7^(6/7)]/(7(ln(t)-c))

Does this look right?

Thanks,
Dao Tuat
 
Last edited:
Can anyone help me out with the second equation? I'm completely lost.
 
that equation for post #3 is not what i got. What did your separation of variables look like?

EDIT: I'm assuming that equation you have is either [tex]y=\frac {7^\frac {6}{7}}{7(ln(t)-c)}[/tex] or [tex]y=7^\frac{6/7}{7(ln(t)-c))}[/tex]
 
Last edited:
Yes, it looked like the first one, which is the same as
y=7*sqrt[-1/(7[ln(t)+c])], correct?

What I did was end up with -[(t^3)/(t^4)]dt=[(y^-6)/(y^2)]dy after seperating

I then integrated and got -ln(t)+c=-1/(7y^7), and then solved for y.

For the other equation, dy/dx - y/x = (x^2)sin2x, I got:
y=[(xsin2x)/4]-[([x^2]cos2x)/2]
 
Do these answeres and approach look right?
 

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