Solving Equations Using the Unit Circle

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kylepetten
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Homework Statement



Find all solutions to the equation below such that -180° [tex]\leq[/tex] x [tex]\leq[/tex] 90°

2sin2x + sinx = 0

Homework Equations


The Attempt at a Solution



2sin2x + sinx = 0

sinx[2sinx + 1] = 0

sin x = 0 sinx= -1/2

x = {0° + 360°n
{-180° + 360°n
n[tex]\epsilon[/tex]I
 
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kylepetten said:

Homework Statement



Find all solutions to the equation below such that -180° [tex]\leq[/tex] x [tex]\leq[/tex] 90°

2sin2x + sinx = 0


Homework Equations





The Attempt at a Solution



2sin2x + sinx = 0

sinx[2sinx + 1] = 0

sin x = 0 sinx= -1/2

x = {0° + 360°n
{-180° + 360°n
n[tex]\epsilon[/tex]I

x = n*pi are the solutions to sin(x) = 0. What about the solutions to sin(x) = -1/2?
 
Mark44 said:
x = n*pi are the solutions to sin(x) = 0. What about the solutions to sin(x) = -1/2?

im not using equations, i am getting my exact values from the unit circle
 
kylepetten said:
im not using equations, i am getting my exact values from the unit circle
Yeah, Mark44! :smile:
 
kylepetten said:
im not using equations, i am getting my exact values from the unit circle
You are using equations, namely 2sin2x + sinx = 0, which you rewrote as sinx(2sinx + 1) = 0.

You have found the solutions to the equation sinx = 0, but you haven't found any for the equation 2sinx + 1 = 0.

BTW, according to your problem description, you need be concerned only with values for which -180° <= x <= 90°. On this interval there are only two solutions to sinx = 0.
 
kylepetten said:
im not using equations, i am getting my exact values from the unit circle

If you post an equation here, it looks like you're using it.
sin x = 1/2 is another possibility. I'm certain that value of x is on the unit circle as well.
you didn't use the condition that -180<=x<=90. An answer such as 360n isn't acceptable here.
 
willem2 said:
If you post an equation here, it looks like you're using it.
sin x = 1/2 is another possibility. I'm certain that value of x is on the unit circle as well.
you didn't use the condition that -180<=x<=90. An answer such as 360n isn't acceptable here.
Probably a typo, but sin x = 1/2 is not a solution. sin x = -1/2 is a solution, though.