- #1

Veronica_Oles

- 142

- 3

## Homework Statement

Solve sin

^{2}x + sinx =0

## Homework Equations

## The Attempt at a Solution

I first factor and get

sinx(sinx + 1) = 0

sinx = 0

x = sin

^{-1}(0)

x= 0

x= π-0 = π

sinx = -1

x= sin

^{-1}(1)

x= π/2

x = π + π/2 = 3π/2

x = { 0, π, 3π/2 }

However when I look at the solution this is correct but they also added 2π and I'm not sure why this is?

It seems like for sinx = 0 they did x = 2π-0 = 2π why is this? I thought that if it's zero you obtain your other value through the sin quadrant.