Solving First Order ODE with Integrating Factor

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Homework Statement


Solve first order ODE

Homework Equations



[tex]\frac{dy}{dx}=x^2+1+\frac{2}{x}y[/tex]
Rearranged
[tex]\frac{dy}{dx}-\frac{2}{x}y=x^2+1[/tex]

The Attempt at a Solution


Integrating factor
[tex]p=\exp(-\int \frac{2}{x})=\exp(-2\ln x)=x^{-2}[/tex]

Multiplying through by the integrating factor
[tex]\frac{d}{dy}(x^{-2}y)=x^{-2}[/tex]

Integrating both sides
[tex]x^{-2}y=-x^{-1}+C[/tex]

Dividing through by [tex]x^{-2}[/tex]
[tex]y=Cx^2-x[/tex]

The problem comes when I use say, Maple to check the answer, it gives

[tex]y=x^3+Cx^2-x[/tex]

Any ideas? Thanks
 
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bobred said:

Homework Statement


Solve first order ODE


Homework Equations



[tex]\frac{dy}{dx}=x^2+1+\frac{2}{x}y[/tex]
Rearranged
[tex]\frac{dy}{dx}-\frac{2}{x}y=x^2+1[/tex]

The Attempt at a Solution


Integrating factor
[tex]p=\exp(-\int \frac{2}{x})=\exp(-2\ln x)=x^{-2}[/tex]

Multiplying through by the integrating factor
[tex]\frac{d}{dy}(x^{-2}y)=x^{-2}[/tex]
No, the right hand side of your original equation was [itex]x^2+ 1[/itex]. Multiplying that by [itex]x^{-2}[/itex] gives [itex]1+ x^{-2}[/itex]. You've dropped the "1".

Integrating both sides
[tex]x^{-2}y=-x^{-1}+C[/tex]

Dividing through by [tex]x^{-2}[/tex]
[tex]y=Cx^2-x[/tex]

The problem comes when I use say, Maple to check the answer, it gives

[tex]y=x^3+Cx^2-x[/tex]

Any ideas? Thanks