Solving First Order ODE with Integrating Factor

  • Thread starter Thread starter bobred
  • Start date Start date
  • Tags Tags
    First order Ode
Click For Summary
SUMMARY

The discussion focuses on solving the first-order ordinary differential equation (ODE) given by \(\frac{dy}{dx}=x^2+1+\frac{2}{x}y\). The correct integrating factor is derived as \(p=\exp(-\int \frac{2}{x})=x^{-2}\). However, a critical error occurs when multiplying through by the integrating factor, leading to the omission of the constant term "1" in the equation. The correct solution, verified by Maple, is \(y=x^3+Cx^2-x\), highlighting the importance of careful manipulation of terms in ODE solutions.

PREREQUISITES
  • Understanding of first-order ordinary differential equations (ODEs)
  • Familiarity with integrating factors in differential equations
  • Knowledge of basic calculus, specifically integration techniques
  • Experience with mathematical software, such as Maple, for verification
NEXT STEPS
  • Study the method of integrating factors in greater detail
  • Learn how to verify ODE solutions using Maple or similar software
  • Explore common mistakes in solving first-order ODEs
  • Investigate other methods for solving first-order ODEs, such as separation of variables
USEFUL FOR

Students and educators in mathematics, particularly those studying differential equations, as well as anyone seeking to improve their problem-solving skills in ODEs.

bobred
Messages
170
Reaction score
0

Homework Statement


Solve first order ODE

Homework Equations



[tex]\frac{dy}{dx}=x^2+1+\frac{2}{x}y[/tex]
Rearranged
[tex]\frac{dy}{dx}-\frac{2}{x}y=x^2+1[/tex]

The Attempt at a Solution


Integrating factor
[tex]p=\exp(-\int \frac{2}{x})=\exp(-2\ln x)=x^{-2}[/tex]

Multiplying through by the integrating factor
[tex]\frac{d}{dy}(x^{-2}y)=x^{-2}[/tex]

Integrating both sides
[tex]x^{-2}y=-x^{-1}+C[/tex]

Dividing through by [tex]x^{-2}[/tex]
[tex]y=Cx^2-x[/tex]

The problem comes when I use say, Maple to check the answer, it gives

[tex]y=x^3+Cx^2-x[/tex]

Any ideas? Thanks
 
Physics news on Phys.org
bobred said:

Homework Statement


Solve first order ODE


Homework Equations



[tex]\frac{dy}{dx}=x^2+1+\frac{2}{x}y[/tex]
Rearranged
[tex]\frac{dy}{dx}-\frac{2}{x}y=x^2+1[/tex]

The Attempt at a Solution


Integrating factor
[tex]p=\exp(-\int \frac{2}{x})=\exp(-2\ln x)=x^{-2}[/tex]

Multiplying through by the integrating factor
[tex]\frac{d}{dy}(x^{-2}y)=x^{-2}[/tex]
No, the right hand side of your original equation was [itex]x^2+ 1[/itex]. Multiplying that by [itex]x^{-2}[/itex] gives [itex]1+ x^{-2}[/itex]. You've dropped the "1".

Integrating both sides
[tex]x^{-2}y=-x^{-1}+C[/tex]

Dividing through by [tex]x^{-2}[/tex]
[tex]y=Cx^2-x[/tex]

The problem comes when I use say, Maple to check the answer, it gives

[tex]y=x^3+Cx^2-x[/tex]

Any ideas? Thanks
 
Thanks
 

Similar threads

Replies
4
Views
3K
Replies
19
Views
3K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
20
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
4
Views
2K