Solving Flux of Electric Field through a Cube of Side L = 2m

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Homework Help Overview

The problem involves calculating the electric flux through the faces of a cube with a given electric field. The cube has a side length of 2m and is centered at the origin, with the electric field defined in vector form.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method for calculating the total flux as the sum of the flux through each face of the cube. There are questions about identifying where the flux is parallel to the faces and where it might be zero. The definition of the normal vector for each surface is also questioned.

Discussion Status

Participants are actively engaging with the problem, exploring the implications of the dot product between the electric field and the normal vectors. Some guidance has been offered regarding the calculations, but there is no explicit consensus on the approach to determining the flux through each individual face.

Contextual Notes

There is a mention of needing to clarify the definitions of the normal vectors for each face of the cube and the implications of the calculations for total flux versus flux through individual sides. Participants are encouraged to visualize the problem with a diagram.

ibaraku
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Homework Statement


A cube of side L = 2m is centered at the origin, with the coordinate axes perpendicular to its faces. Find the flux of the electric field E = (15N/C)i + (27N/C)j + (39N/C)k through each face of the cube


Homework Equations



phi total = (E * n) delta A


The Attempt at a Solution



Ok, so I know that
phi total = phi 1 + phi 2 + ... + phi 6

what I am confused about is how do I know where the flux is parallel to the faces of cube, where is it zero?

Thanks
 
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ibaraku said:

Homework Statement


A cube of side L = 2m is centered at the origin, with the coordinate axes perpendicular to its faces. Find the flux of the electric field E = (15N/C)i + (27N/C)j + (39N/C)k through each face of the cube


Homework Equations



phi total = (E * n) delta A


The Attempt at a Solution



Ok, so I know that
phi total = phi 1 + phi 2 + ... + phi 6

what I am confused about is how do I know where the flux is parallel to the faces of cube, where is it zero?

Thanks

(E*n) is the dot product between [tex]\vec{E}[/tex] and [tex]\hat{n}[/tex]. You are given [tex]\vec{E}[/tex], so what is the definition of [tex]\hat{n}[/tex] for any surface? What is [tex]\hat{n}[/tex] for each surface of the cube? Once you find these, you just compute the dot product and then integrate over the area of each surface to get your phis.
 
gabbagabbahey said:
(E*n) is the dot product between [tex]\vec{E}[/tex] and [tex]\hat{n}[/tex]. You are given [tex]\vec{E}[/tex], so what is the definition of [tex]\hat{n}[/tex] for any surface? What is [tex]\hat{n}[/tex] for each surface of the cube? Once you find these, you just compute the dot product and then integrate over the area of each surface to get your phis.

Yeah I get that
[((15N/C)i + (27N/C)j + (39N/C)k] . i = (15N/C) a^2
"" "" "" "" . -i = -(15N/C) a^2
...
...

I am just wondering how do I know where one of this calculations will be zero, where will the flux be parallel to the sides of the cube, how do I recognize that?
 
ibaraku said:
Yeah I get that
[((15N/C)i + (27N/C)j + (39N/C)k] . i = (15N/C) a^2
"" "" "" "" . -i = -(15N/C) a^2
...
...

I am just wondering how do I know where one of this calculations will be zero, where will the flux be parallel to the sides of the cube, how do I recognize that?
Flux is a scalar quantity...it will be neither parallel nor perpendicular to any given side. Why do you have an a^2 there? And for which face is [tex]\hat{n}=+\hat{i}[/tex]?Is it the same for all faces? Can you show your whole solution?
 
gabbagabbahey said:
What is [tex]\hat{i} \cdot \hat{i}[/tex], how about [tex]\hat{i} \cdot \hat{j}[/tex] and [tex]\hat{i} \cdot \hat{k}[/tex]?

1, 0, 0

I see, so for this problem

[(15N/C)a^2 + (-15N/C)a^2 + (27N/C)a^2 + (-27N/C)a^2 + (39N/C)a^2 + (-39N/C)a^2] = 0

Thanks
 
ibaraku said:
1, 0, 0

I see, so for this problem

[(15N/C)a^2 + (-15N/C)a^2 + (27N/C)a^2 + (-27N/C)a^2 + (39N/C)a^2 + (-39N/C)a^2] = 0

Thanks

If by a you mean L, then yes but you have calculated the TOTAL flux. The question asks for the flux through each side. You should draw a diagram, where you label each side and give the flux through each side.
 

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