The discussion focuses on deriving the acceleration of a charge \( q \) with mass \( m \) between two parallel plates separated by distance \( d \) and subjected to a potential difference \( \Delta V \). The correct approach involves using the equation \( ma = Eq \) and substituting the electric field \( E \) with the expression \( E = \Delta V / d \). The final expression for acceleration is \( a = \frac{q \Delta V}{md} \). The key takeaway is the relationship between electric field, potential difference, and plate separation.
PREREQUISITESStudents in physics, electrical engineering majors, and anyone studying electromagnetism who seeks to understand the dynamics of charged particles in electric fields.
You could find the electric field.alanwangcot said:Homework Statement: Two parallel plates are separated by a distance d and a potential difference ΔV is applied between them. Write an expression for the acceleration of a charge q with a mass m between the plates
Homework Equations: E=F/q, C=q/V, E=1/2CV^2
Tried using ma=Eq, then subbing E for 1/2CV^2, but can't seem to be getting anywhere. How can I get to the answer which is a=qΔV/md.