Solving for Acceleration: 8.3kg Block & 25.3° Angle

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Homework Help Overview

The discussion revolves around a physics problem involving a block of mass 8.3 kg being pulled on a frictionless surface by a force of 53.0 N at an angle of 25.3° above the horizontal. Participants are exploring how to set up equations to find the acceleration of the block, particularly focusing on the role of the angle in the calculations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss separating the applied force into horizontal and vertical components using trigonometric ratios. There are questions about the correct angles to use in the equations and how to express the forces in terms of mass and acceleration.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on how to approach the problem. Some guidance has been offered regarding the use of trigonometric functions, but there is still uncertainty about the correct setup of the equations, particularly concerning the angle involved.

Contextual Notes

Participants have noted the challenge of using the correct angle in their calculations, as well as the need to clarify the components of the applied force. There is an indication that assumptions about the angle may need to be revisited.

chaotixmonjuish
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A block of mass 8.3 kg is pulled along a horizontal frictionless floor by a cord that exerts a force of 53.0 N at an angle 25.3° above the horizontal. What is the magnitude of the acceleration of the block?

I'm just wondering how I set up an equation with an angle.
 
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Separate the applied force into its horizontal and vertical components using the trigonometric ratios or use the method of tension co-efficients.
 
That's where I'm having a problem.

would it be something like:

y=(mass)(sin(30)a)
x=(mass)(cos(30)a)
 
How about [tex]F_x = F(cos (\frac{\pi}{6}))[/tex] ?
 
wow, how did you get that
 
chaotixmonjuish said:
That's where I'm having a problem.

would it be something like:

y=(mass)(sin(30)a)
x=(mass)(cos(30)a)
Yes, something like that. But of course the angle isn't 30 degrees.
 

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