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shadowice
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Homework Statement
A simple harmonic oscillator has a frequency of 3.4 Hz. It is oscillating along x, where x(t) = A cos(ωt + δ). You are given the velocity at two moments: v(t=0) = 1.8 cm/s and v(t=.1) = -19.3 cm/s.
1)Calculate A.
2)Calculate δ.
Homework Equations
w= 2pi*f = 21.36 rad/s
v(t) = -wAsin(wt +δ)
The Attempt at a Solution
1) v(0) = -21.36*A*sin(w0 +δ) =1.8 cm/s
1.8/[-21.36*sin(δ)]=A
Solved for A and substituted that into 2nd equation A
v(.1) = -21.36*A*sin(21.36*.1 +δ) =-19.3 cm/s
-21.36*(1.8/[-21.36*sin(21.36*0 +δ)])*sin(21.36*.1 +δ) =-19.3 cm/s
1.8*sin(δ)*sin(.1 +δ)=-19.3 cm/s
sin(δ)*sin(21.36*.1 +δ)=-10.72
from here is where I am not really sure what to do that 21.36*.1+δ throws me off
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