Solving for Angle Theta | Calculating Angles Made Easy

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SUMMARY

The discussion focuses on solving for angle theta (x) in the equation derived from a geometric problem involving trigonometric identities. The equation presented is 600^2 = [250-150sinx-150cos(40-x)]^2 + [500sin60 + 150cosx + 150sin(40-x)]^2. Participants are encouraged to follow the Homework Forum Rules by posting complete problems and their attempts at solutions to facilitate effective assistance.

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CivilSigma
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I am having trouble with calculating angle theta:

I have derived:

600^2 = [250-150sinx-150cos(40-x)]^2 + [500sin60 + 150cosx +150sin(40-x) ] ^2

how do I solve for x in this case?
 
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Please follow the HW Forum Rules and use the HW template, i.e., post the complete problem and your attempt at a solution.
 

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