Solving for Average Force: Physics Homework Help for a 0.47 kg Ball

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SUMMARY

The discussion focuses on calculating the average force exerted on a 0.47 kg ball that falls from a height of 34 m and rebounds to a height of 24 m, with contact time of 1.8 ms. The relevant equations include vf^2=2gh and vf=sqrt(2gh), which are essential for determining the final velocity before impact. The impulse formula is recommended as a straightforward method to solve for the average force, emphasizing its importance in physics problem-solving.

PREREQUISITES
  • Understanding of kinematic equations, specifically vf^2=2gh.
  • Familiarity with the concept of impulse in physics.
  • Basic knowledge of force and time relationship in mechanics.
  • Ability to perform calculations involving mass, height, and velocity.
NEXT STEPS
  • Study the impulse-momentum theorem to understand its application in force calculations.
  • Learn how to derive final velocity using kinematic equations in different scenarios.
  • Explore real-world applications of average force in collision physics.
  • Practice similar problems involving different masses and heights to reinforce concepts.
USEFUL FOR

Students studying physics, particularly those tackling mechanics and force calculations, as well as educators seeking to enhance their teaching methods in problem-solving strategies.

bunton33
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Homework Statement



After falling from rest from a height of 34 m, a 0.47 kg ball rebounds upward, reaching a height of 24 m. If the contact between ball and ground lasted 1.8 ms, what average force was exerted on the ball?


Homework Equations



vf^2=2gh

vf=sqrt 2gh.

force*time=2sqrt(2gh)


The Attempt at a Solution



i have tried to plug in but i cannot seem to get it correct. help please!
 
Physics news on Phys.org
Look up the concept of "impulse" in your textbook or Wikipedia. The impulse formula will make short work of this problem!
 

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