Solving for b_1: Help Needed with 2A=h(b_{1}+b_{2})?

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Homework Help Overview

The discussion revolves around solving the equation 2A = h(b1 + b2) for b1. Participants are exploring the process of rewriting equations, particularly focusing on algebraic manipulation.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the steps involved in isolating b1, including rewriting the equation and considering the division by h. There are questions about the correct form of the equation after manipulation.

Discussion Status

There is an active exchange of ideas regarding the algebraic steps needed to isolate b1. Some participants provide guidance on the manipulation of the equation, while others confirm or correct each other's reasoning. The discussion reflects a collaborative effort to clarify the process without reaching a definitive conclusion.

Contextual Notes

Participants express a sense of struggle with rewriting equations, indicating a learning context where foundational algebraic skills are being reinforced. There is a mention of a desire to improve in this area, suggesting ongoing challenges with similar problems.

GLprincess02
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I know you all are probably sick of me posting these kind of "easy" problems, but rewriting equations is one of those things that I just seem to struggle with. So that being said, can I get help with [tex]2A=h(b_{1}+b_{2})[/tex]? I need to solve for [tex]b_{1}[/tex]. Maybe if someone just gave me the first step, I could get the rest ?
 
Last edited:
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[tex]2A=h(b_{1}+b_{2})[/tex].
[tex]2A = hb_{1}+hb_{2}[/tex].
[tex]2A-hb_{2} = hb_{1}[/tex].

So how would you solve for [tex]b_{1}[/tex]?
 
Wouldn't you divide both sides by h?
 
yes you would.
 
So the final answer would be [tex]\frac{2A-b_{2}}{h}=b_{1}[/tex] ?
 
no it would be [tex]b_{1} = \frac{2A-hb_{2}}{h}[/tex] or [tex]b_{1} = \frac{2A}{h} - b_{2}[/tex]
 
Last edited:
Oh you're right, I just forgot the 2nd h in my equation.

And thanks for all your help. I think I'm starting to get this more, so hopefully this will be my last rewriting problem!
 

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