- #1

- 77

- 1

## Homework Statement

A ball is thrown horizontally from the top of a building and lands 20.0m away from it. If the ball is initially thrown at a velocity of 10.0m/s, how high is the building? How long does it take for the ball to reach the ground?

## Homework Equations

dv = Viv * t + 1/2a * t

## The Attempt at a Solution

dh (horiz.distance) = 20.0m

Vh = 10.0m/s

Viv (vertical init. velocity) = 0m/s

a = -9.8m/s

dv (vert. distance) = ?

t = ?

I'm confused because I'm missing two of the variables which are needed in the equation that will solve this problem...? (dv and t)