Solving for Frictional Force in Banked Curve Problem

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Homework Help Overview

The discussion revolves around a physics problem involving a banked curve, where a car is moving at a constant speed. The problem requires determining the frictional force, normal force, and the coefficient of friction for a car on a banked curve with specific parameters.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the forces acting on the car, including weight, normal force, and friction. Some participants suggest the importance of drawing a free body diagram to clarify the forces involved.

Discussion Status

Participants are actively discussing the setup of the problem, with some providing alternative interpretations of the forces. There is mention of previously provided answers, but the original poster expresses difficulty in arriving at those figures. Others have shared insights that may help clarify the approach to solving the problem.

Contextual Notes

There is a lack of a detailed diagram of forces, which some participants note could aid in understanding the problem. The original poster has also indicated that they have received answers but are struggling to reconcile them with their calculations.

TheRaiderNati
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Homework Statement



A certain curve on a freeway has a radius of 200m and is banked at an angle of 25°. A 200-kg car moves around the curve at constant speed.

1. If the speed of the car is 35m/s, what friction force is needed to keep the car moving in a circle?
2. If the speed of the car is 35m/s, what normal force acts on the car?
3. If the speed of the car is 35m/s, what is the minimum value of the coefficient of friction?

Homework Equations


a_{cent}=\frac{v^{2}}{R}
F_{cent}=m*a_{cent}


The Attempt at a Solution


I have been attempting to solve this problem for about a week now but have but hopelessly stuck.

1. I tried to set up the equation so that the x-component of Weight plus the friction force (since the friction force points inwards) was equal to the Centripetal Force, like so:

F_{x} = Wsin(25) + f = m*a_{cent}
(Where f = friction force)

But I couldn't seem to get the right answer.

2.I figured that since the car has no vertical acceleration the sum of the net forces in the Y direction should equal to zero. In this case the only forces with Y components are the weight and normal force. Therefore:
F_{y} = N - Wcos(25) = 0

However, this also produced an incorrect result.


3. I know that I can simply divide the force of friction by the Normal force to get the coefficient, so I guess I don't really need help on this one.

Answers were provided to me for these questions, but I still can't seem to get the same figures:
1. 2820N
2. 22900N
3. 0.123
3. 0.123

Thanks in advanced for any help.
 
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If the diagram of the forces is shown one finds it easier to give help.
 
No diagram of the forces was given. Only a picture showing a car on a banked curve.
 
Usually one starts the solution of this problem with a diagram of the forces.

So what I meant was the diagram that YOU have to try to do showing these forces.
 
I think that the answers for (1) and (2) are 282N and 2290N respectively.
 
So I ended up solving the remainder of the questions using the equations I found here.

Also, the free body diagram on that website was essentially what I had drawn out initially. I think the trigonometry involved was what was throwing me off.

The only problem I am now having issues solving is finding the minimum possible speed of the car if the coefficient of friction is .20.
EDIT: Never mind, just figured that one out too. Thanks for the help guys.
 
Let us call the coefficient of friction μ. Then the frictional force will be given by
frictional force = μN where N is the normal reaction of the road on the car.

I do not think that you will have any problem in finding the speed.
 

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