Solving for Horizontal Displacement: Ball on a String

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The discussion revolves around calculating the horizontal displacement of a ball on a string that moves in a vertical circle before the string breaks at the highest point. The centripetal acceleration is given as a, and the radius of the circle is R. The initial confusion involved determining the ball's velocity and direction after the string breaks. It was clarified that the ball travels horizontally first before falling to the ground, which simplifies the problem to kinematics. Ultimately, the participant successfully solved the problem after manipulating the equations correctly.
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Homework Statement


A ball on a string moves in a vertical circle of radius R at a constant speed with a centripetal acceleration a. At its
lowest point, the ball is a negligible height above the ground. After several revolutions, the string breaks at the highest
point in the motion. In terms of R, a, and g, find the horizontal displacement of the ball from the time the string breaks.


Homework Equations


ac=v2/r


The Attempt at a Solution


I found v = √acr but I don't know where to go from here.
 
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If it breaks at it's highest point, what direction will the ball be traveling?

How high off the ground was it when it was released?

Doesn't it just become a simple kinematic problem?
 
If it breaks at its highest point it will travel horizontally first, but then reach the ground.

It is 2R off the ground when it was released.

OMG I GOT IT! Thanks so much! I just had trouble manipulating the equation. Embarrassing.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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