Solving for k1 and k2 in a Simple Electrical Engineering Question

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Discussion Overview

The discussion revolves around solving for the constants k1 and k2 in the equation for charge q(t) in an electrical engineering context. Participants explore the relationship between current and charge, focusing on the mathematical approach to derive the constants from given initial conditions.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • The original poster (OP) suggests using the integral of i(t) to find q(t), indicating uncertainty about the approach.
  • Another participant corrects the OP, stating that the relationship should start with the equation i = dq/dt instead of using the integral directly.
  • A later reply notes that solving for constants in this manner is relevant to differential equations and Fourier series, suggesting a broader context for the problem.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the initial approach to solving the problem, as the OP's method is challenged by another participant. The discussion remains unresolved regarding the best method to apply.

Contextual Notes

The discussion does not clarify the assumptions behind the initial conditions provided or the specific definitions of the variables involved. There is also no resolution on the mathematical steps required to derive k1 and k2.

wk1989
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Hi, I'm doing an introductory electrical engineering course on my own and so far have gotten a few pages into the book. I understand pretty much all the problems so far except for this one.
"The charge entering a terminal of an element is given by the equation
Code:
q(t) = (k1)t^2+(k2)t
Where 1 and 2 are subscripts.
If i(0) = -5 A and i(1)=+5A, find k1 and k2."

I think you have to use the integral of i(t) which gives q(t) but I'm not sure how to start. Any help would be appreciated.
 
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Not the integral of i(t), instead start with this basic equation:

i = \frac{dq}{dt}
 
thanks!
 
Just a note to the OP, such type of solving for constants can be seen in solving particular solutions for differential equations and Fourier series (if you take it a step ahead.) Just something to remember, so that when you actually see it later on, it'll be a piece of cake.
 

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