Solving for Magnetic Flux in a Square Loop

[louza8]

Homework Statement

A 3.0 magnetic field makes a 55deg angle with a square loop 25cm on a side

Homework Equations

MFlux = BACos(theta)

The Attempt at a Solution

=3*.25²*cos(55)
=0.11Wb

Answer is to 2 sigfigs. This is a masteringphysics problem, and I'm wondering if I'm missing something here or if MP has the wrong answer stored.

 

[rl.bhat]

The relevant equation given by you is for a field making an angle θ with the vertical.

In the problem the angle is with the plane of the coil. So

MFlux = BAsinθ.

 

[louza8]

thanks