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Displacement current and magnetic flux through a wire loop

  1. May 2, 2016 #1
    1. The problem statement, all variables and given/known data
    A long straight wire has a line charge, λ that varies in time according to: λ = λ0e(-βt). A square loop of dimension, a, is adjacent to the wire (at a distance a away from the wire). Calculate expressions for the displacement current at the center of the wire loop and the magnetic flux through the loop.

    2. Relevant equations
    λ = λ0e(-βt)
    I = dq/dt
    B = μ0I/2πr
    displacement current: i = ∈0e/dt
    Magnetic flux: Φm = ∫A ⋅ dB

    3. The attempt at a solution
    I know I can take the derivative of the charge to get current, which I need to find the magnetic field, which I need to find magnetic flux. However, I'm not sure what to do about the length component of λ. How can I get an expression for the charge without knowing a finite length? Once I get the current though, finding the flux and displacement current should be simple.

    To get magnetic flux, I can first derive the current equation and then derive the equation for the magnetic field with respect to current to give dB = μ0dI/2πr. Then I can use the magnetic flux equation above to find an equation for the flux.

    For the displacement current, I can use the relationship E = volts/meter, which I can manipulate to give E = IR/1.5a, where 1.5a is the distance to the center of the wire loop from the current-carrying wire. Taking the derivative with respect to current will give me an equation for dE, which I can use with the formula for the derivative of the electric flux. I can then use that with the formula for the displacement current to get an equation for the displacement current.


    For reference, the square wire loop is oriented with one side parallel to the line charge, at a distance a from the wire. This means that the sides of the square perpendicular to the wire go from distance a to 2a.
     
    Last edited: May 2, 2016
  2. jcsd
  3. May 7, 2016 #2
    Thanks for the post! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
     
  4. May 7, 2016 #3

    haruspex

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    I'm no expert in this area, but you do not seem to be getting any replies, so...
    I cannot understand why there would be a magnetic flux through the square with the wire and square coplanar. The electric field would be radial, and the displacement current density at the square would therefore be in the plane of the square (time derivative of ε0E). By symmetry, the magnetic flux would seem to cancel everywhere. Am I missing something?
     
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