Solving for sin(7.5) using half-angle formula

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The discussion focuses on calculating sin(7.5 degrees) using the half-angle formula. The initial steps involve applying the formula sin(x/2) = √((1 - cos(x))/2) with x set to 15 degrees. The poster expresses confusion over how to derive the denominator of 8 in the provided answer options, which are \((5 + \sqrt{5})/8\) and \((5 - \sqrt{5})/8\). Other participants suggest that the answers might be incorrect and indicate a possible typo in the answer sheet. The conversation highlights the importance of verifying calculations and answer sources in trigonometric problems.
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[SOLVED] Finding sin(7.5)

Homework Statement


Find sin(7.5) using sin\frac{x}{2} = \sqrt{(\frac{1 - cosx}{2})}


Homework Equations


sin2x = 2sinxcosx
cos(x-y) = coxcosy + sinxsiny


The Attempt at a Solution



sin\frac{15}{2} = \sqrt{(\frac{1 - cos15}{2})}

= \sqrt{(\frac{1 - cos(45-30)}{2})}

= \sqrt{(\frac{1 - (\frac{\sqrt(2)+\sqrt(6)}{4})}{2})}


After this I don't know what to do. I would like some help please. Thanks.
 
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I think you're done (assuming 7.5 means 7.5 degrees, not 7.5 radians). Unless you want to plug it into a calculator and get a number.
 
In our answer sheet, the answer for this question is:

\frac{5 + \sqrt{5}}{8}}

or

\frac{5 - \sqrt{5}}{8}}

So I am really confused as to how to get 8 as the denominator. Please help. Thanks.

(Note: 7.5 is degrees.)
 
Last edited:
rum2563 said:
In our answer sheet, the answer for this question is:

\frac{5 + \sqrt{5}}{8}}

or

\frac{5 - \sqrt{5}}{8}}

So I am really confused as to how to get 8 as the denominator. Please help. Thanks.

(Note: 7.5 is degrees.)

You don't want to get those answers. They are wrong. And how can there be two of them? You are right.
 
Yea, I think there must be a typo on the answer sheet. Anyways, thanks to both Dick and Avodyne for analyzing the problem.
 

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