Solving for the Velocity and Height in a Difficult Kinematics Problem

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SUMMARY

The discussion focuses on solving a kinematics problem involving a ball thrown from a height h, which hits the ground after 1.07 seconds at a distance of 27.5 meters and an angle of 67° with the horizontal. To determine the height h, participants suggest using kinematic equations and breaking down the motion into horizontal and vertical components. The final velocity can be calculated using the sine and cosine of the angle, leading to the determination of both the magnitude and direction of the initial velocity.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of vector decomposition
  • Familiarity with projectile motion concepts
  • Ability to apply trigonometric functions in physics
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  • Study the derivation and application of kinematic equations in two dimensions
  • Learn how to decompose vectors into their components using sine and cosine
  • Explore projectile motion problems involving angles and heights
  • Practice calculating initial velocities from final velocities in projectile motion
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Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators looking for problem-solving strategies in these topics.

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Homework Statement


In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.07 s. later, at distance d = 27.5 m from the building and at angle θ = 67° with the horizontal.

4-36.gif


(a) Find h

(b) What is the velocity at which the ball is thrown?
magnitude
angle ° relative to the horizontal

(c) Is that angle above or below the horizontal?


Homework Equations





The Attempt at a Solution



Ive been staring at this problem for a while now and am out of ideas any help would be greatly appreciated.
 
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Did you try making a list of Δt, Δ(x or y), Vi, Vf, and a for both the x and the y directions, then seeing if you can apply a kinematic equation to solve for unknown variables?

For instance Vfy =sin67(magnitude of Vf) and Vfx = cos67(magnitude of Vf), so if you could use kinematics in one direction to solve for the magnitude of Vf, you would then know the final velocity in the other direction as well.
 

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