Solving for time given a messy displacement equation

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Homework Help Overview

The problem involves determining the time required for an elevator to travel a specified distance, given a complex displacement equation that describes its acceleration over time. The context is rooted in kinematics, specifically focusing on motion under variable acceleration.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to integrate the acceleration function to find the displacement and subsequently solve for time, but expresses difficulty in isolating time in their final equation. Some participants suggest substituting specific values into the distance equation to explore potential simplifications.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on substituting values to clarify the relationship between distance and time. There is an ongoing exploration of interpretations regarding the total distance and time of the trip, but no consensus has been reached yet.

Contextual Notes

There seems to be some confusion regarding the interpretation of the distance ##D##, whether it refers to the total distance for the entire trip or a specific point along the journey. This ambiguity is influencing the discussion and the approaches being considered.

Rations
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I'm having some trouble with this problem (adapted from K&K 1.23).

Homework Statement


An elevator is programmed to start from rest and accelerate according to
\begin{align*}
a(t) &= \frac{a_m}{2}\left[1 - \cos\left(\frac{2\pi t}{T}\right)\right] &\mbox{for }0\leq t\leq T \\
a(t) &= -\frac{a_m}{2}\left[1 - \cos\left(\frac{2\pi t}{T}\right)\right] &\mbox{for }T\leq t\leq 2T
\end{align*} where ##a_m## is the maximum acceleration and ##2T## is the total time for the trip.
What is the time required for a trip of distance ##D##?

Homework Equations


##v = \int adt##
##x = \int vdt##

The Attempt at a Solution


Assume for a moment that ##0 \leq t \leq T##. Integrating then yields
\begin{align*}
x &= \frac{a_m}{2}\left[\frac{t^2}{2} + \left(\frac{T}{2\pi}\right)^2\cos\frac{2\pi t}{T}\right]
\end{align*}
Letting ##t = 0##, we find
\begin{align*}
x_0 &= \frac{a_m}{2}\left(\frac{T}{2\pi}\right)^2
\end{align*}
It follows that
\begin{align*}
D &= x - x_0 = \frac{a_m}{2}\left[\frac{t^2}{2} + \left(\frac{T}{2\pi}\right)^2\left(\cos\frac{2\pi t}{T} - 1\right)\right]
\end{align*}
But I'm not seeing a way to hammer this into a useful expression for ##t##. Perhaps there is an error in the way the problem is worded?
 
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The time for the half trip is T. Have you tried substituting T for t in your distance equation?
 
gneill said:
The time for the half trip is T. Have you tried substituting T for t in your distance equation?
I'm not sure I understand. How would doing that help me find a general expression for ##t##, given any value of ##D##?
 
Rations said:
I'm not sure I understand. How would doing that help me find a general expression for ##t##, given any value of ##D##?
If I've interpreted the question correctly, D is the distance for the whole trip, which takes a total time 2T, so . . . . . (gneill is pointing you in the right direction)
 
Rations said:
I'm not sure I understand. How would doing that help me find a general expression for ##t##, given any value of ##D##?
TonyS said:
If I've interpreted the question correctly, D is the distance for the whole trip, which takes a total time 2T, so . . . . . (gneill is pointing you in the right direction)
Ah, I thought ##D## was any point along the trip. Sorry for the confusion.
 

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