Solving for $\vec{\upsilon}$ from Diagrams

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SUMMARY

The discussion centers on solving for the velocity vector, \(\vec{\upsilon}\), using the equations \(\vec{\upsilon} = \frac{\vec{\Delta} V}{B d}\) and \(\vec{\upsilon} = u E\). The user initially calculated \(\vec{\upsilon}\) as \(1.25 \times 10^{-5} V/(B)(0.001m)\) and attempted to find the magnetic field \(B\) but arrived at an incorrect value of \(1.7857 \times 10^{-7}\). The problem was ultimately resolved by a peer, confirming the collaborative nature of the forum.

PREREQUISITES
  • Understanding of vector notation in physics
  • Familiarity with electromagnetic equations, specifically \(\vec{\upsilon} = \frac{\vec{\Delta} V}{B d}\)
  • Basic knowledge of units and conversions in physics
  • Ability to interpret and analyze diagrams related to physics problems
NEXT STEPS
  • Study the derivation and applications of the equation \(\vec{\upsilon} = \frac{\vec{\Delta} V}{B d}\)
  • Explore the relationship between electric fields and velocity in electromagnetic contexts
  • Learn about the significance of magnetic field strength \(B\) in various physical scenarios
  • Review problem-solving techniques for physics diagrams and vector analysis
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators looking for collaborative problem-solving examples in academic forums.

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Homework Statement


http://img3.imageshack.us/img3/2178/9b26f2dd8dd8a8686c9c8c2.th.png

Homework Equations




[itex]\vec{\upsilon}= \vec{\Delta} V / ( B d)[/itex]

[itex]\vec{\upsilon}= u E[/itex]

The Attempt at a Solution



from the diagram , we have [itex]\vec{\upsilon} = 1.25*10^-5 V/(B)(0.001m)[/itex]

using the second formula ( 1.25*10^-5 )V/(B)(0.001m) = 3.5*10^-5 (240V)(0.12m)


in which I got B = 1.7857*10^-7, which is wrong...
why?
 
Last edited by a moderator:
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Thank you very much for info, I was wondering why no1 bother to reply...
The link somehow manage to show a picture on my computer.

Well, the question have been solved by my friend. It is no longer a problem.
Thank you again for telling me though
 

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