Solving for velocity from relativistic momentum

[chris_0101]

Homework Statement

I need help rearranging the relativistic momentum equation in terms of velocity.

Homework Equations

p = (mv)/sqrt(1-((v^2)/(c^2)))

The Attempt at a Solution

p = (mv)/sqrt(1-((v^2)/(c^2)))
p(sqrt(1-((v^2)/(c^2)))) = mv
sqrt(1-((v^2)/(c^2))) = mv/p
1-((v^2)/(c^2)) = (mv/p)^2
1- (mv/p)^2 = ((v^2)/(c^2))

This is where I am stuck. The part that confuses me is the fact that I have velocity on both sides. If I were to continue I believe that the velocities cancel each other out.

Thanks for the help.

 

[physalpha]

from
1-((v^2)/(c^2))=(mv/p)^2
((m^2/p^2)+(1/c^2))v^2=1
v= ?
solve next step.