Solving for Velocity of Particle in 2D Plane

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SUMMARY

The discussion focuses on calculating the velocity of a particle in a 2D plane under the influence of two forces: vector F1 = (3i - 2j) N and vector F2 = (4i - 7j) N, acting on a 1.70 kg mass initially at rest. The correct velocity components at 9.4 seconds are confirmed to be (38.7i - 49.7647j) m/s, with the particle's direction being 307.87 degrees. A common mistake highlighted is the misuse of the final velocity in calculations, emphasizing the importance of applying standard constant acceleration equations and considering initial positions.

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PeterFer
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Homework Statement



Two forces, vector F 1 = (3 i - 2 j) N and vector F 2 = (4 i - 7 j) N, act on a particle of mass 1.70 kg that is initially at rest at coordinates (-1.70 m, +4.25 m).

i know that the components of the velocity at 9.4 seconds are (38.7i - 49.7647j)m/s
i also know that the direction the particle is moving at 9.4 seconds is 307.87 degrees

Homework Equations





The Attempt at a Solution


some how everything I do brings me to (363.78i - 467.788j)m which is wrong
 
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Welcome to PF!

Hi PeterFer! Welcome to PF! :smile:

You don't need, and shouldn't use, the final velocity …

(it's misled you into using s = vt)

just use one of the standard constant acceleration equations

(and don't forget to add on the initial position). :wink:
 


ah yea thank you, i ended up realizing that myself but thank you anyway
 

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