Solving for Wavelength of a Harmonic Wave

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To solve for the wavelength of a harmonic wave, first determine the frequency by calculating the number of vibrations per second, which is 40.0 vibrations in 30.0 seconds, yielding a frequency of 1.33 Hz. Next, calculate the speed of propagation by dividing the distance traveled (425 cm) by the time taken (10.0 s), resulting in a speed of 42.5 cm/s. The relationship between speed, wavelength, and frequency is given by the formula: speed = wavelength × frequency. Rearranging this formula allows for the calculation of wavelength. By substituting the known values into the equation, the wavelength can be determined.
physics_ash82
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ok I need help starting this problem. I always have trouble seeing which formula to use so ant thoughts would be helpful

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 40.0 vibrations in 30.0 s. Also, a given maximum travels 425 cm along the rope in 10.0 s. What is the wavelength?
 
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physics_ash82 said:
It is observed that the oscillator that generates the wave completes 40.0 vibrations in 30.0 s.
This gives you the frequency.

physics_ash82 said:
Also, a given maximum travels 425 cm along the rope in 10.0 s.
This gives you the speed of propagation.

physics_ash82 said:
What is the wavelength?
You know frequency and speed and you need wavelength. Do you know any formula relating these quantities?
 
so I would use the formula a=Aw^2cos(wt)
 
physics_ash82 said:
so I would use the formula a=Aw^2cos(wt)
No. You'd use a formula relating the frequency, speed and wavelength of a traveling harmonic wave.
 
Answer

Ok I hate seeing people trouble through homework
especially if your name is ashley (personal joke):biggrin:

Anyway the formula you need is pretty simple and straightforward

speed= wavelength * frequency

I don't quite know how to place greek letters in this forum but that's basically it.

you should know how to get the speed which is simply distance/time
and the frequency should be obtained by the number of vibrations per second.

Just solve for lambda err wavelength and plug in numbers :D
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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