Solving for x in 0=−(4.90 m/s^2)t^2 -(8.00 m/s)t + 30m

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Homework Help Overview

The problem involves a quadratic equation in the form of 0=−(4.90 m/s²)t² −(8.00 m/s)t + 30m, where the original poster expresses confusion about solving for "x," which is not present in the equation. The context suggests a focus on solving for the variable "t."

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the quadratic formula and clarify the coefficients for the equation. There is a question about identifying the correct values for "a," "b," and "c" in the context of the quadratic formula.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the use of the quadratic formula and discussing the nature of the roots. There is an acknowledgment of the positive determinant, indicating the potential for real solutions, but clarity on the original poster's confusion remains a topic of discussion.

Contextual Notes

There is a misunderstanding regarding the variable "x," which is not part of the equation, leading to questions about the setup and interpretation of the problem.

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Homework Statement



0=−(4.90 m/s^2)t^2 -(8.00 m/s)t + 30m
i am asked to solve for x but having problems

Homework Equations





The Attempt at a Solution

 
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There's no "x" in the equation, but if you are solving for "t", use the quadratic equation.
 
k thanks but I am still kind of stuck is -8.00t b and -4.90 a and 30 c. for the quadratic formula
 
The determinant of the second degree equation is positive, which thereby yields two distinct real roots.
 
im sorry but can u explain that simplier
 
Well, the thing inside the radical sign, it is positive, sqrt((-8.00)^2-4*(-4.90)(30))=sqrt(652), which is real.
 
thanks a bunch
 

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