Why Can't We Rewrite Newton's Second Law as f = m*s/t^2?

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Homework Help Overview

The discussion revolves around the interpretation of Newton's Second Law, specifically questioning the validity of rewriting the equation f = m*a as f = m*s/t^2. Participants are exploring the relationship between force, mass, acceleration, and displacement in the context of classical mechanics.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the reasoning behind the incorrect formulation of force in terms of displacement over time squared. Some explore the implications of constant versus variable acceleration and the conditions under which certain equations apply.

Discussion Status

There is an active exploration of the concepts involved, with some participants providing insights into the relationships between acceleration, velocity, and distance. However, there is no explicit consensus on the reasoning or a definitive resolution to the questions raised.

Contextual Notes

Participants are considering scenarios such as constant acceleration and the implications of initial velocity being zero. The discussion also touches on the complexities introduced when acceleration is not constant.

Abhijith S. Raj
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We all know that f = m*a. But why can't we write this as f = m * s/t^2 ?
I know this is wrong. But what is the reason?? Need opinion on this.
Thankyou.
 
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Abhijith S. Raj said:
We all know that f = m*a. But why can't we write this as f = m * s/t^2 ?
I know this is wrong. But what is the reason?? Need opinion on this.
Thankyou.
You can't do it because ##\displaystyle \ a\ne \frac{s}{t^2} \ ## .
 
a = dv/dt. Ya now i get it.
 
Abhijith S. Raj said:
a = dv/dt. Ya now i get it.
If initial velocity is zero, and acceleration is constant, then the final velocity is v = at, but the average velocity is v/2 . The average velocity multiplied by time gives distance, so that s = (1/2)at*t = (1/2)at2, a = 2a/t2 .

Therefore, you could write f = 2ma/t2, provided that initial velocity is zero, and acceleration is constant.
 
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Thanks
 
if accelaration is not constant then?
 
akashpandey said:
if acceleration is not constant then?
Then, ... all bets are off. That's also true if the initial (or final) velocity isn't zero.
 
sorry but i don't understand.
please can u tell this mathematically. pleasezx
 

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