Solving for Y in a differential equation

[Badgerspin]

I'm sure there's something very simplistic I'm overlooking in this one. That generally tends to be the case, but for the life of me, I can't seem to find it.

The following equation is what I started with:

dy/dø = [(e^y)(sin^2ø)]/(y*sec^2ø)

I have it worked down to the following:

(-e^-y)(y+1)=(sin^3ø)/3 + c

How would I reduce this to get y by itself?

Any help is appreciated. Thanks in advance.

 

[fzero]

You can't solve this for y in terms of elementary functions. There's a function called the product logarithm defined around this kind of expression: http://en.wikipedia.org/wiki/Lambert_W_function

 

[Badgerspin]

My mistake, that should be secø, not sec^2ø.

Also, thank you. We haven't gone that far in my class as far as I recall, but this book has a tendency to place equations in earlier sections that are not covered until later sections.