Solving Fourier Transform of f(x)=1/(x^2+6x+13)

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Homework Help Overview

The discussion revolves around finding the Fourier transform of the function f(x) = 1/(x^2 + 6x + 13). Participants are exploring the integration process involved in computing this transform.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration technique required for the Fourier transform, with some expressing uncertainty about how to proceed with the evaluation. There are questions regarding what constitutes a serious attempt at solving the problem.

Discussion Status

The discussion appears to be ongoing, with participants seeking clarification on the integration process and the expectations for demonstrating effort. There is no clear consensus on the approach to take, and some participants express frustration with the requirements for posting.

Contextual Notes

There are mentions of forum rules that require a serious attempt at the problem, which may be influencing the tone and direction of the discussion.

saxen
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Homework Statement


Hi y'all, ran into some trouble with a Fourier transform

Im supposed to find the Fourier transform of

f(x)=\frac{1}{x^{2}+6x+13}


Homework Equations



Not that I know

The Attempt at a Solution



I tried integrating this with no luck.

All help is as usual very much appreciated!
 
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What are your thoughts on how to do the integration?
 
vela said:
What are your thoughts on how to do the integration?

Sorry, but I don't understand what you mean. Do you mean how I technically evaluate it?
 
What I'm getting at is the rules of the forum say you need to show a serious attempt at doing the problem yourself. Simply saying "I tried but couldn't figure it out" doesn't cut it.
 
vela said:
What I'm getting at is the rules of the forum say you need to show a serious attempt at doing the problem yourself. Simply saying "I tried but couldn't figure it out" doesn't cut it.

Well then, not much else to then lock thread I guess. Will call a friend instead. Thank you for reading though.
 

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