Proving inverse Fourier transform of 1/(1+x^2) = 1/(1+x^2)

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SUMMARY

The inverse Fourier transform of the function \( F(t) = \sqrt{\frac{\pi}{2}} e^{-t} \) for \( t > 0 \) and \( F(t) = \sqrt{\frac{\pi}{2}} e^{t} \) for \( t < 0 \) is proven to equal \( \frac{1}{1+x^2} \). The integral \( \frac{1}{\sqrt{2\pi}} \int F(t) e^{itx} dt \) is evaluated by splitting the real line into two intervals: \( (-\infty, 0) \) and \( (0, \infty) \). This method simplifies the integration process, avoiding complications with infinite limits.

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Homework Statement


F(t) = sqrt(π/2)e-t for t>0
F(t) = sqrt(π/2)et for t<0
In other words the question asks to solve this integral: 1/sqrt(2π) ∫F(t)eitxdt and show that it equals 1/(1+x2)

Homework Equations


F(t) = sqrt(π/2)e-t for t>0
F(t) = sqrt(π/2)et for t<0
1/sqrt(2π) ∫F(t)eitxdt

The Attempt at a Solution


I want to use complex numbers but these functions are analytic and so I can not do this using residues. A naive approach to integrating with respect to t is straightforward but the limits cause the result to be infinity. How should I approach this properly?
 
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Vitani11 said:

Homework Statement


F(t) = sqrt(π/2)e-t for t>0
F(t) = sqrt(π/2)et for t<0
In other words the question asks to solve this integral: 1/sqrt(2π) ∫F(t)eitxdt and show that it equals 1/(1+x2)

Homework Equations


F(t) = sqrt(π/2)e-t for t>0
F(t) = sqrt(π/2)et for t<0
1/sqrt(2π) ∫F(t)eitxdt

The Attempt at a Solution


I want to use complex numbers but these functions are analytic and so I can not do this using residues. A naive approach to integrating with respect to t is straightforward but the limits cause the result to be infinity. How should I approach this properly?
Break up the real line into ##-(\infty, 0)## and ##(0,\infty)##, then do two separate integrals. Each integral is really easy.
 

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