Solving Friction Problem in Physics - Cns/Oslo

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SUMMARY

The discussion focuses on solving a physics problem involving friction coefficients for two objects tied together on a horizontal table. Object 1 has a mass of 2 kg and a friction coefficient of 0.1, while Object 2 has a mass of 4 kg and a friction coefficient of 0.15. The applied force on Object 2 is 60 N. The solution involves applying Newton's second law separately for each object, calculating individual frictional forces, and recognizing that both objects share the same acceleration. The final step is to combine the equations to solve for acceleration.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of friction coefficients and their application
  • Basic algebra for solving equations
  • Familiarity with free-body diagrams
NEXT STEPS
  • Study the application of Newton's second law in multi-object systems
  • Learn how to calculate frictional forces using coefficients
  • Explore free-body diagram techniques for visualizing forces
  • Investigate the relationship between mass, force, and acceleration in physics
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of friction in multi-object systems.

Oslo
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Hello!

I have just started physics here in Norway, and we have a home assignement due to friday. I sat all yesterday trying to figuer out what friction coefficient to use in my assignment. Here is the assignment:

Two objects are lying on an horizontal table, tied together with a very light rope, object 1 has the mass of 2Kg and object 2 has the mass of 4Kg.

Object one has friction coefficient = 0.1
Object two har friction coefficient = 0,15

The Force applied on the rope tied to object 2 has a force of 60N...

Object 1----------object 2----------------> F=6N

Do i calculate with 0.25 as a friction coef.? or both individually intergrated into F-(Mju*g+(m1+m2)/(m1+m2) . To find the acceleration

Please give me some hints.

Hopefully you understand my english :)

thanks
Cns/Oslo
 
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Consider each object separately. Apply Newton's second law (the sum of all of the forces that an object experiences is equal to it's mass times it's acceleration) for each object separately in the direction of F. Each object has it's own frictional force (which can be calculated). Both objects share the same acceleration though. You will end up with two equations with the same tension in both. Add the two equations up and solve for the acceleration.
 
Thank you so much, you have been to great help!
 
Glad I could help you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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